Tugas Diagnosa LAN IP Address(Subnetting)

5. Dik : IP Address sebuah network =192.168.11.0/23

Dit  : Buatlah menjadi 16 subnetwork!

Jawab : 192.168.11.0/23

            16=2ⁿ ------ n=4
            32-27=5          -----------     2⁵=32 host/subnet

            Subnet                                                                    Range IP

192.168.11.0/27                   ------     192.168.11.1/27- 192.168.11.30/27

192.168.11.32/27                 ------     192.168.11.33/27-192.168.11.62/27

            192.168.11.64/27                 ------     192.168.11.65/27-192.168.11.94/27
            192.168.11.96/27                 ------     192.168.11.97/27-192.168.11.126/27
            192.168.11.128/27               ------     192.168.11.129/27-192.168.11.158/27
            192.168.11.160/27               ------     192.168.11.161/27-192.168.11.190/27
            192.168.11.192/27               ------     192.168.11.193/27-192.168.11.222/27
            192.168.11.224/27               ------     192.168.11.225/27-192.168.11.254/27

192.168.12.0/27                   ------     192.168.12.1/27- 192.168.12.30/27

192.168.12.32/27                 ------     192.168.12.33/27-192.168.12.62/27

            192.168.12.64/27                 ------     192.168.12.65/27-100.100.0.94/27
            192.168.12.96/27                 ------     192.168.12.97/27-192.168.12.126/27
            192.168.12.128/27               ------     192.168.12.129/27-192.168.12.158/27
            192.168.12.160/27               ------     192.168.12.161/27-192.168.12.190/27
            192.168.12.192/27               ------     192.168.12.193/27-192.168.12.222/27
            192.168.12.224/27               ------     192.168.12.225/27-192.168.12.254/27

6. Dik : IP Address sebuah network =192.168.10.14/26

Dit  : Buatlah menjadi 7 subnetwork!

Jawab : 192.168.10.14/26

            2ⁿ >7  ------  n=3
            26+3=29

32-29=3

2³=8  ------ 8 host/subnet

            Subnet                                                               Range IP

192.168.10.14/29                 ------       192.168.10.15/29- 192.168.10.20/29 

192.168.10.22/29                 ------       192.168. 10.23/27-192.168.10.28/29

            192.168.10.30/29                 ------       192.168.10.31/27-192.168.10.36/29
            192.168.10.38/29                 ------       192.168.10.39/27-192.168.10.44/29
            192.168.10.46/29                 ------       192.168.10.47/27-192.168.10.52/29
            192.168.10.54/29                 ------       192.168.10.55/27-192.168.10.60/29
            192.168.10.62/29                 ------       192.168.10.63/27-192.168.10.68/29
7. Dik : IP Address sebuah network =192.168.112.0/20

Dit  : Tentukan alokasi subnetwork yang masing-masing terdiri atas 600 host!

Jawab : 192.168.112.0/20

            600+2 < 2ⁿ
            n=10

32-10=22

            Subnet                                                               Range IP

192.168.112.0/22     ------ 192.168.112.1/22-192.168.114.92/22           

192.168.116.0/22     ------ 192.168.116.1/22-192.168.118.92/22

            192.168.120.0/22     ------ 192.168.120.1/22-192.168.122.92/22
            192.168.124.0/22     ------ 192.168.124.1/22-192.168.124.92/22
  
8. Dik : IP Address sebuah network =100.100.10.10/28

Dit  : Tentukan alokasi subnetwork yang masing-masing terdiri atas 8 host!

Jawab : 100.100.10.10/28

            32-28=4
            2⁴=16 ------ 16/8=2 subnetwork

2ⁿ=2

n=1 ------ 28+1=29

            Subnet                                                                   Range IP

100.100.10.10/29                     ------         100.100.10.11/29-100.100.10.16/29

            100.100.10.18/29                     ------         100.100.10.19/29-100.100.10.24/29